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Question: When a large bubble rises from the bottom of a lake to the surface. Its radius doubles. If atmospher...

When a large bubble rises from the bottom of a lake to the surface. Its radius doubles. If atmospheric pressure is equal to that of column of water height H, then the depth of lake is

A

H

B

2H

C

7H

D

8H

Answer

7H

Explanation

Solution

(P0+hρg)×43πr3\left( P _ { 0 } + h \rho g \right) \times \frac { 4 } { 3 } \pi r ^ { 3 }=P0×43π(2r)3P _ { 0 } \times \frac { 4 } { 3 } \pi ( 2 r ) ^ { 3 }

Where, h = depth of lake

hρg=7P0h \rho g = 7 P _ { 0 }h=7×Hρgρg=7Hh = 7 \times \frac { H \rho g } { \rho g } = 7 H