Question

When a gas in a closed vessel was heated so as to increase its temperature by$5^{o}C$, there occurred an increase of 1% in its pressure. The original temperature of the gas was

• A. $500^{o}C$
• B. $273^{o}C$
• C. $227^{o}C$
• D. $50^{o}C$

Answer 1

Answer: (C)

$227^{o}C$

Answer 2

$P \propto T \Rightarrow \frac{P_{1}}{P_{2}} = \frac{T_{1}}{T_{2}} \Rightarrow \frac{P_{1}}{(1.01)P_{1}} = \frac{T_{1}}{T_{1} + 5}$

$\Rightarrow T_{1} = 500\mspace{6mu} K$ = 227°C.