Solveeit Logo

Question

Physics Question on Moving charges and magnetism

When a current of 5mA5 \,mA is passed through a galvanometer having a coil of resistance 15Ω15 \, \Omega, it shows full scale deflection. The value of the resistance to be put in series with the galvanometer to convert it into a voltmeter of range 010V0-10 \,V is :

A

1.985×103Ω1.985 \times 10^3 \, \Omega

B

2.045×103Ω2.045 \times 10^3 \, \Omega

C

2.535×103Ω2.535 \times 10^3 \, \Omega

D

4.005×103Ω4.005 \times 10^3 \, \Omega

Answer

1.985×103Ω1.985 \times 10^3 \, \Omega

Explanation

Solution

ig=5×103Ai_g = 5 \times 10^{-3} A
G=15ΩG = 15 \, \Omega
Let series resistance be R.
V=ig(R+G)V = i_g (R + G)
10=5×103(R+15)10 = 5 \times 10^{-3} (R + 15)
R=200015=1985=1.985×103ΩR = 2000 - 15 = 1985 = 1.985 \times 10^3 \, \Omega