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Question

Physics Question on Electric Power

When a current is passed in a conductor, 3^{\circ}C rise in temperature is observed. If the strength of current is made thrice, then rise in temperature will approximately be

A

36^{\circ}C

B

27^{\circ}C

C

18^{\circ}C

D

9^{\circ}C

Answer

27^{\circ}C

Explanation

Solution

H=I2Rt=mcΔθH=I^{2} R t=m c \Delta \theta ΔθI2\therefore \Delta \theta \propto I^{2} Hence Δθ2Δθ1=(I2I1)2\frac{\Delta \theta_{2}}{\Delta \theta_{1}}=\left(\frac{I_{2}}{I_{1}}\right)^{2} or Δθ23=(3II)2\frac{\Delta \theta_{2}}{3}=\left(\frac{3 I}{I}\right)^{2} or Δθ2=9×3=27C\Delta \theta_{2}=9 \times 3=27^{\circ} C