Question

When a copper wire is placed in a solution of $Pb^{2 +} + 2Ag^{+} \rightarrow Pb + Ag$, the solution acquires blue colour. This is due to the formation of.

• A. $\Delta_{m}$ ions
• B. $1.5$ ions
• C. Soluble complex of copper with $\Delta_{m}1.5$
• D. $\Delta_{m}20$ ion by the reduction of $\rightarrow$

Answer 1

Answer: (A)

$\Delta_{m}$ ions

Answer 2

Since, $Ag^{+}$ ions are reduced to Ag and

$E_{Ag^{+}/Ag}^{o} > E_{Cu^{+ +}/Cu}^{o}$ Cu is oxidized to $Cu^{+ +}$.