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Question: When a circular coil of radius \[1\,m\] and 100 turns is rotated in a horizontal uniform magnetic fi...

When a circular coil of radius 1m1\,m and 100 turns is rotated in a horizontal uniform magnetic field, the peak value of emf Induced is 100V100\,V . The coil is unwound and then rewound into a circular coil of radius 2m2\,m . If it is rotated, now with the same speed, under similar conditions, the new peak value of emf developed is:
A. 50V50V
B. 25V25V
C. 100V100V
D. 200V200V

Explanation

Solution

Let's get a sense of the peak value before we get into the question. The peak value of induced emf is the largest value of alternating emf. Now, in order to answer the question, we will use a ratio to compare the peak value in both instances, first when the radius was 1m1m and then after the radius was doubled. If the emf peak values in the two scenarios are V1{V_1} and V2{V_2} , then we may use the ratio to determine the required answer.

Complete step by step answer:
A coil with NN turns and area AA rotates with angular velocity (ω)\left( \omega \right) in a uniform magnetic field BB. The peak value of the induced emf (Vmax)\left( {{V_{\max }}} \right) is therefore given by,
(Vmax) = NABω.\left( {{V_{\max }}} \right){\text{ }} = {\text{ }}NAB\omega .

Since the radius has been doubled, the area of the coil in the second case is 4A4A. However, because the length of wire required for a turn is doubled in the second scenario, the number of turns will be N2\dfrac{N}{2}.If the peak values of the emf in the two situations are V1{V_1} and V2{V_2}.We have;
V1V2=100V2=NABω[(N2)×(4A)Bω]\dfrac{{{V_1}}}{{{V_2}}} = \dfrac{{100}}{{{V_2}}} = \dfrac{{NAB\omega }}{{\left[ {\left( {\dfrac{N}{2}} \right) \times \left( {4A} \right)B\omega } \right]}}
100V2=12\Rightarrow \dfrac{{100}}{{{V_2}}} = \dfrac{1}{2}
From which
V2=200V\therefore {V_2} = 200\,V
Therefore, if it is rotated, now with the same speed, under similar conditions, the new peak value of emf developed is 200V200\,V.

Therefore, the correct option is D.

Note: The difference between peak and rms value should not be misconstrued by students while solving problems. The maximum or highest value of current obtained in a single cycle is known as the peak value of current. The rms value of current, on the other hand, is defined as the root mean square value of current that may be determined when heat is dissipated in the resistor.