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Question

Physics Question on Moving charges and magnetism

When a charged particle moving with velocity v\vec{ v } is subjected to a magnetic field of induction B\vec{ B } the force on it is non-zero. This implies that

A

angle between v\vec{ v } and B\vec{ B } is necessarily 9090^{\circ}

B

angle between v\vec{ v } and B\vec{ B } can have any value other than 9090^{\circ}

C

angle between v\vec{ v } and B\vec{ B } can have any value other than zero and 180180^{\circ}

D

angle between v\vec{ v } and B\vec{ B } is either zero or 180180^{\circ}

Answer

angle between v\vec{ v } and B\vec{ B } can have any value other than zero and 180180^{\circ}

Explanation

Solution

When a charged particle qq is moving in a uniform magnetic field B\vec{ B } with velocity v\vec{ v } such that angle between v\vec{ v } and B\vec{ B } be θ\theta, then due to interaction between the magnetic field produced due to moving charge and magnetic force applied, the charge qq experiences a force which is given by
F=qvBsinθF=q v B \sin \theta
If θ=0\theta=0^{\circ} or 180180^{\circ}, then sinθ=0\sin \theta=0
F=qvBsinθ=0\therefore F=q v B \sin \theta=0
Since, force on charged particle is non-zero, so angle between v\vec{ v } and B\vec{ B } can have any value other than zero and 180180^{\circ}.
Note : Force experienced by the charged particle is Lorentz force.