Solveeit Logo

Question

Question: When a ceiling fan is switched on, it makes \(10\) revolution in the first \(3\) \(s\). Assuming a u...

When a ceiling fan is switched on, it makes 1010 revolution in the first 33 ss. Assuming a uniform angular acceleration, how many rotations it will make in the next 33 ss?
A. 1010
B. 2020
C. 3030
D. 4040

Explanation

Solution

Split the whole situation in two parts. First part will deal with the motion occurring in the first 33 seconds and the second part will deal with the motion occurring in the next 33 seconds. Use the kinematics equations for rotational motion and find the final unknowns in the first part and use them to find the final unknowns in the second part.

Complete step by step answer:
First part: When the ceiling fan is switched on, the initial angular velocity will be zero ω0=0{\omega _0} = 0.The time taken by the ceiling fan to complete 1010 revolutions is 3s3\,s. Let the final angular velocity in the first part be ω1{\omega _1}, then we can use the formulae mentioned above to find this,
ω1=0+αt α=ω1t  {\omega _1} = 0 + \alpha t \\\ \Rightarrow\alpha = \dfrac{{{\omega _1}}}{t} \\\
Substituting this value in equation (3)\left( 3 \right)
θ=ω0t+12(ω1t)t2 θ=(2ω0+ω12)t  \theta = {\omega _0}t + \dfrac{1}{2}\left( {\dfrac{{{\omega _1}}}{t}} \right){t^2} \\\ \Rightarrow\theta = \left( {\dfrac{{2{\omega _0} + {\omega _1}}}{2}} \right)t \\\
\Rightarrow\theta = \left( {\dfrac{{\left( 2 \right)\left( 0 \right) + \left( {{\omega _1}} \right)}}{2}} \right)\left( 3 \right) \\\ \Rightarrow\theta = \dfrac{{3{\omega _1}}}{2} \\\
1010 revolutions means that the angle rotated will be
10 \times 2\pi $$$rad$$$ = 20\pi radrad,
ω1=2θ3 ω1=(2)(20π)3 ω1=40π3{\omega _1} = \dfrac{{2\theta }}{3}\\\ \Rightarrow{\omega _1} = \dfrac{{\left( 2 \right)\left( {20\pi } \right)}}{3}\\\ \Rightarrow{\omega _1} = \dfrac{{40\pi }}{3} rads\dfrac{{rad}}{s}.
From here we can get the acceleration of the fan is,
α=(40π3)3 α=40π9\alpha = \dfrac{{\left( {\dfrac{{40\pi }}{3}} \right)}}{3}\\\ \therefore\alpha = \dfrac{{40\pi }}{9} rads2\dfrac{{rad}}{{{s^2}}}

Second part:
Here, the initial velocity will be ω1=40π3{\omega _1} = \dfrac{{40\pi }}{3} rads\dfrac{{rad}}{s} and the time is 33seconds. Using the equation (3)\left( 3 \right) we can get the angle rotated by the fan in the next 33 seconds and then the number of revolutions can be obtained.
θ=(40π3)(3)+12(40π9)(3)2 θ=40π+20π θ=60π  \theta = \left( {\dfrac{{40\pi }}{3}} \right)\left( 3 \right) + \dfrac{1}{2}\left( {\dfrac{{40\pi }}{9}} \right){\left( 3 \right)^2} \\\ \Rightarrow\theta = 40\pi + 20\pi\\\ \therefore\theta = 60\pi \\\
The angle rotated by the fan in the next 33 ss is 60π60\pi radrad. The fan revolves 11 time and rotates by an angle of 2π2\pi radrad, then for 60π60\pi $raditwillrotateit will rotate\dfrac{{60\pi }}{{2\pi }} = 30$ times.

Thus, it will make 3030 rotations in the next 3s3\,s.Hence,option C is correct.

Note: Always split the questions into parts according to the given data. Find the final angular velocity, find the final velocity in the current part to find the rest unknowns in the next part as the body will be carrying the final angular velocity in some part as initial angular velocity in the next part. Remember the kinematics equations for rotational motion.