Question

When a block of mass $M$ is suspended by a long wire of length $L$, the length of the wire becomes $(L+l)$. The elastic potential energy stored in the extended wire is:

• A. Mgl
• B. MgL
• C. $\frac12Mgl$
• D. $\frac12MgL$

Answer 1

Answer: (C)

$\frac12Mgl$

Answer 2

The correct option is (C) :$\frac12MgL$