Question

When a biochemical reaction is carried out in laboratory from outside of human body in the absence of enzyme, the rate of reaction obtained is $10^{-6}$ times, then activation energy of the reaction in the presence of enzyme is

• A. $\frac{6}{RT}$
• B. P is required
• C. different from $E_a$ obtained in laboratory
• D. cannot say any things

Answer 1

Answer: (C)

different from $E_a$ obtained in laboratory

Answer 2

The correct answer is C:Different from $E_a$ obtained in laboratory
In a laboratory setting, when a biochemical reaction is conducted outside the human body without the involvement of enzymes, the reaction rate is observed to be $10^{-6}$ times slower than the activation energy of the reaction. This differs from the activation energy obtained in the laboratory because, for a specific chemical reaction, there is a distinct difference in the activation energy when enzymes are present
compared to when they are absent. This variation in activation energy is described by the;
Arrhenius equation: $K = Ae^{(\frac{-Ea}{RT}).}$
It indicates that the activation energy takes on different values depending on whether enzymes are involved or not.