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Question: When a ball is thrown up vertically with a velocity v<sub>0</sub> it reaches a height h. If one wish...

When a ball is thrown up vertically with a velocity v0 it reaches a height h. If one wishes to triple the maximum height then the ball be thrown with a velocity

A

√3 v0

B

3 v0

C

9v0

D

3/2 v0

Answer

√3 v0

Explanation

Solution

v2 = 2gh or v = 2gh\sqrt { 2 g h } , i.e., v1v2=h1 h2\frac { \mathrm { v } _ { 1 } } { \mathrm { v } _ { 2 } } = \sqrt { \frac { \mathrm { h } _ { 1 } } { \mathrm {~h} _ { 2 } } }

∴ v2 = √3 v0