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Physics Question on Nuclear physics

When 92U235{ }^{92} U _{235} undergoes fission 0.1%0.1 \% of its original mass is changed into energy. How much energy is released if 1 kg1 \,kg of 92U235{ }^{92} U _{235} undergoes fission

A

9×1010 J9 \times 10^{10} \,J

B

9×1011 J9 \times 10^{11}\, J

C

9×1012 J9 \times 10^{12}\, J

D

9×1013 J9 \times 10^{13}\, J

Answer

9×1013 J9 \times 10^{13}\, J

Explanation

Solution

⇒0.1100×1 kg=11000 kg=10−3kg\Rightarrow \frac{0.1}{100} \times 1\, kg =\frac{1}{1000} \,kg =10^{-3} kg
Using the equation
E=mc2E = mc ^{2}
=10−3×(3×108)2=10^{-3} \times\left(3 \times 10^{8}\right)^{2}
=10−3×9×1016=10^{-3} \times 9 \times 10^{16}
E=9×1013 JE =9 \times 10^{13} \,J