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Question: When \(_{92}{{U}^{235}}\) bombarded by \(_{0}{{n}^{1}}\) which one of the following is NOT obtained ...

When 92U235_{92}{{U}^{235}} bombarded by 0n1_{0}{{n}^{1}} which one of the following is NOT obtained
(A)54Xe142+38Sr90+4(0n1) (B)56Ba139+36Kr94+3(0n1) (C)55Cs144+37Rb90+2(0n1) (D)40Zr94+52Te138+3(0n1) \begin{aligned} & {{(A)}_{54}}X{{e}^{142}}{{+}_{38}}S{{r}^{90}}+4\left( _{0}{{n}^{1}} \right) \\\ & {{(B)}_{56}}B{{a}^{139}}{{+}_{36}}K{{r}^{94}}+3\left( _{0}{{n}^{1}} \right) \\\ & {{(C)}_{55}}C{{s}^{144}}{{+}_{37}}R{{b}^{90}}+2\left( _{0}{{n}^{1}} \right) \\\ & {{(D)}_{40}}Z{{r}^{94}}{{+}_{52}}T{{e}^{138}}+3\left( _{0}{{n}^{1}} \right) \\\ \end{aligned}

Explanation

Solution

Nuclear fission is the process by which heavy nucleus splits into lighter ones. During the time of fission more energy is released. The energy released is called binding energy and some kinetic energy is released during this time. The resultant small nuclei produced as result of fission is called daughter nuclei. The number of neutrons produced in this time may be two, three or more.

Complete answer:
Nuclear fission is the process by which a heavy nucleus splits into lighter ones. During the time of fission more energy is released. Also neutrons are also released. As fission is a chain reaction, during fission it produces more number of neutrons. The Uranium-235 absorbs a neutron there by obtaining a lighter nucleus. The energy released during the time of fission is known as the binding energy. The resultant small nuclei produced as result of fission is called daughter nuclei. The number of neutrons produced in this time may be two, three or more. Some of the energy is released as kinetic energy also. In general, nuclear fission is the splitting or breaking of atoms. And the process of repeated splitting is known as the chain reaction.
Thus when Uranium-235 is bombarded with neutrons the following lighter nuclei are formed.
That is,
92U235+0n156Ba141+36Kr92+3(0n1)_{92}{{U}^{235}}{{+}_{0}}{{n}^{1}}{{\to }_{56}}B{{a}^{141}}{{+}_{_{{}}36}}K{{r}^{92}}+3\left( _{0}{{n}^{1}} \right)

So, the correct answer is “Option B”.

Note:
Nuclear fission is the process by which a heavy nucleus splits into lighter ones. While the Uranium-235 splits into lighter daughter nuclei, the reactant side must balance with the product side. That is, the proton number and mass number on both sides must be equal. The fission process is a continuous process and hence known as a chain reaction.