Question
Question: When \(9.65\)ampere current was passed for \(1.0\) hour into nitrobenzene in an acidic medium, the a...
When 9.65ampere current was passed for 1.0 hour into nitrobenzene in an acidic medium, the amount of p-aminophenol produced is ________.
A. 10.9g
B. 109.0g
C. 9.81g
D. 98.1g
Solution
To solve this question, you must recall the formula for Faraday’s first law of electrolysis. It states that, “the amount of any substance that is deposited or liberated at an electrode is directly proportional to the quantity of electricity passing through the electrolytic cell.
Formula used: w=ZIt
Where, wis the amount of substance liberated or deposited.
I is the current passed through the cell
t is the time for which current is passed.
And, Zis the electrochemical equivalent of a substance
Z is given by 96500E
Where E is the equivalent weight of the substance liberated or deposited.
This gives the equation as: w=96500EIt.
Complete step by step solution:
It is given that, 9.65 ampere current was passed for 1.0 hour, which is the same as 3600 seconds.
The reduction of nitrobenzene to para amino phenol requires 4 electrons per molecule of nitrobenzene.
Or we can say that one mole of nitrobenzene requires 4 moles of electrons to be reduced to para amino phenol.
The n-factor of the reaction is 4
Thus, the equivalent weight of para amino phenol is =4109.
Now, we can find the amount of para amino phenol formed using the equation,
w=96500EIt
Substituting the values we get,
w=96500(4109)(9.65)(3600)
⇒w=4×96500109×9.65×3600
Solving this, we get:
∴w=9.81gm
Therefore the amount of para amino phenol deposited is 9.81 grams.
Note: The electrochemical equivalent of a substance is the amount of substance deposited or liberated during the electrolysis by the passage of quantity of electricity equal to 1 Faraday which is given as 96500 coulombs per mole. Equivalent weight of an element or compound depends upon the reaction in which that species is involved.