Question

When $9.65\,A$ current was passed for $1.0\, hour$ into nitrobenzene in acidic medium, the amount of p-aminophenol produced is_____.

• A. 9.81 g
• B. 10.9 g
• C. 98.1 g
• D. 109.0 g

Answer 1

Answer: (A)

9.81 g

Answer 2

The reaction involved is

We know $n=\frac{I \times t}{F}=\frac{9.65 \times 3600}{96500}=0.36\, mol$

From the above reaction, we can see that $4\, mol$ of electrons are required to reduce nitrobenzene to $p$ -aminophenol.

Therefore, $0.36$ mol of electrons will reduce $\frac{0.36}{4}=0.09$ mol of nitrobenzene to $p$ -aminophenol.

Mass of $p$ -aminophenol produced = Molar mass $\times$ No. of moles

$=109.14\, g\, mol ^{-1} \times 0.09\, mol =9.81\, g$