Question
Chemistry Question on Thermodynamics
When 5 moles of He gas expand isothermally and reversibly at 300 K from 10 litre to 20 litre, the magnitude of the maximum work obtained is _____ J. [nearest integer] (Given : R = 8.3 J K-1 mol-1 and log 2 = 0.3010)
Answer
The correct answer is 8630
Wrev = –2.303 nRT log10 (V2/V1)
= –2.303 × 5 × 8.3 × 300 × log10(20/10)
≈ –8630 J