Question

When 300 J of heat is added to 25 gm of sample of a material its temperature rises from 25⁰C to 45⁰C. the thermal capacity of the sample and specific heat of the material are respectively given by

• A. 15 J/⁰C, 600 J/kg ⁰C
• B. 600 J/⁰C, 15 J⁰/kg ⁰C
• C. 150 J/⁰C, 60 J/kg ⁰C
• D. None of these

Answer 1

Answer: (A)

15 J/⁰C, 600 J/kg ⁰C

Answer 2

Thermal capacity = mc = $\frac{Q}{\Delta T} = \frac{300}{45 - 25} = \frac{300}{20} = 15J/{^\circ}C$Specific heat = $\frac{\text{Thermal capacity}}{\text{Mass}}$

= $\frac{15}{25 \times 10^{- 3}} = 600J/kg{^\circ}C$