Question

When $3.0g$ of carbon is burnt in $8.00g$ of oxygen, $11.00g$ of carbon dioxide is produced. What mass of carbon dioxide will be formed when $3.00g$ of carbon is burnt in $50.00g$ of oxygen? Which law of chemical combinations will govern your answer?

Answer 1

We need to know that mass is a proportion of the measure of an issue that an article contains. The mass of an article is made in contrast with the standard mass of one kilogram. The kilogram was initially characterized as the mass of one liter of fluid water at $4^\circ C$ (the volume of a fluid changes somewhat with temperature).

Complete answer:
In the given details are given below,
When $3.0g$ of carbon is burnt in $8.00g$ of oxygen, $11.00g$ of carbon dioxide is produced.
We have to calculate the mass of carbon dioxide that will be formed. $3.00g$ of carbon is burnt in $50.00g$ of oxygen.
First the balanced chemical equation is given below,
$C + {O_2} \to C{O_2}$
According to the given condition, when $3.0g$ of carbon is singed in $8.00g$ oxygen, $11.00g$ of carbon dioxide is created.
$3g + 8g \to 11g$
Then,
The absolute mass of reactants = mass of carbon + mass of oxygen
Therefore,
The absolute mass of reactants = $3g + 8g$
The absolute mass of reactants = $11g$ .
Where,
The absolute mass of reactants = Total mass of items
Along these lines, the law of protection of mass is demonstrated.
Then, at that point, it likewise portrays that the carbon dioxide contains carbon and oxygen in a fixed proportion by mass, which is $3:8$ .
Along these lines it further demonstrates the law of consistent extents. $3.0g$ of carbon should likewise consolidate with $8.00g$ of oxygen in particular. This implies that $\left( {50g - 8g} \right) = 42g$ of oxygen will remain unreacted.
The excess $42g$ of oxygen will be left unresponsive. For this situation likewise, just $11g$ of carbon dioxide will be shaped.

Note:
Your mass is similar regardless of where you go in the universe; your weight, then again, changes from one spot to another. Mass is estimated in kilograms; despite the fact that we as a rule talk about weight in kilograms, strictly speaking it ought to be estimated in Newton, the units of power.