Question
Question: When \(20J\) of work was done on a gas, \(40J\)of heat energy was released. If the initial internal ...
When 20J of work was done on a gas, 40Jof heat energy was released. If the initial internal energy of the gas was 70J. Then what will be the final internal energy of the system.
& A.50J \\\ & B.60J \\\ & C.90J \\\ & D.110J \\\ \end{aligned}$$Solution
First of all let us find out the change in internal energy. This change in internal energy is equal to the difference of the total heat energy and the work done by the system. The work done on the system is mentioned as negative and energy released is mentioned as negative. These all may help you to solve this question.
Complete step by step answer:
the change in internal energy is expressed as,
ΔU=Ufinal−Uinitial
In accordance with the first law of thermodynamics, change in internal energy is equal to the difference of the total heat energy and the work done by the system. This can be expressed in the mathematical way as,
ΔU=Q−W
Therefore, we can equate both the equations together,
Ufinal−Uinitial=Q−W
As mentioned in the question, the heat energy has been released from the system. According to the conventions, the heat energy released is given as negative and vice versa. Therefore we can write that,
Q=−Q
And the work done is mentioned as work done on the system. As per the conventions, the work done on the system is mentioned as negative. Therefore we can write that,
W=−W
Hence we can substitute this in the equation,
That is,
Ufinal−Uinitial=−Q−(−W)=−Q+W
The value of work done on the gas is given as,
W=20J
Heat energy released is given as,
Q=40J
The initial internal energy is given as,
Uinitial=70J
Substituting these values in the equation will give,