Question

When 2 amperes current is passed through a tangent galvanometer, it gives a deflection of 30^o. For 60^o deflection, the current must be

• A. 1 amp
• B. $2 \sqrt { 3 } \mathrm { amp }$
• C. 4 amp
• D. 6 amp

Answer 1

Answer: (D)

6 amp

Answer 2

$i \propto \tan \phi \Rightarrow \frac { i _ { 1 } } { i _ { 2 } } = \frac { \tan \phi _ { 1 } } { \tan \phi _ { 2 } }$

$\Rightarrow \frac { 2 } { i _ { 2 } } = \frac { \tan 30 } { \tan 60 } \Rightarrow i _ { 2 } = 6 \mathrm { amp }$