Question

When 2 amp. current is passed through a tangent

galvanometer, it gives a deflection of 30°. For 60° deflection, The current must be

• A. 1 amp.
• B. $2 \sqrt { 3 }$amp.
• C. 4 amp.
• D. 6 amp.

Answer 1

Answer: (D)

6 amp.

Answer 2

By using

$i \propto \tan \theta \Rightarrow \frac { i _ { 1 } } { i _ { 2 } } = \frac { \tan \theta _ { 1 } } { \tan \theta _ { 2 } } \Rightarrow \frac { 2 } { i _ { 2 } } = \frac { \tan 30 ^ { \circ } } { \tan 60 ^ { \circ } } = \frac { 1 } { 3 } \Rightarrow i _ { 2 } = 6$amp.