Question

When 12.0 g of carbon reacted with limited quantity of oxygen, 57.5 kcal of heat was produced, Calculate the number of moles of CO produced ($\Delta$fH (CO2) = – 94.05 kcal, $\Delta$fH (CO) = – 21.41 kcal.

• A. 0.54 mol
• B. 0.46 mol
• C. 0.64 mol
• D. 0.74 mol

Answer 1

Answer: (A)

0.54 mol

Answer 2

12g C = 1 mole, suppose CO produced = x moles.

Then CO2 produced = (1 – x) mole

$\therefore$ x (– 21.41) + (1 – x) (– 94. 05) = – 57.5.

This on solving gives x = 0.54 mole.