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Question: When 1.04 g of \(\mathrm { BaCl } _ { 2 }\) is present in \(10 ^ { 5 }\) g of solution the concen...

When 1.04 g of BaCl2\mathrm { BaCl } _ { 2 } is present in 10510 ^ { 5 } g of solution the concentration of solution is

A

0.104ppm0.104 p p m

B

C

D

104 ppm

Answer

Explanation

Solution

=1.04105×106=10.4ppm= \frac { 1.04 } { 10 ^ { 5 } } \times 10 ^ { 6 } = 10.4 \mathrm { ppm }