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Question

Physics Question on Electromagnetic induction

When 100 V d.c. is applied across a coil, a current of 1 A flows through it. When 100 V a.c. of 50 Hz is applied to the same coil only 0.5 A flows. The inductance of the coil is

A

0.55 mH

B

5.5 mH

C

0.55 H

D

55 mH

Answer

0.55 H

Explanation

Solution

R = VI=1001=100Ω\frac{V}{I} = \frac{100}{1} = 100 \, \Omega and Z = VI=1000.5=200Ω\frac{V}{I} = \frac{100}{0.5} = 200 \, \Omega
L = Z2R22πν=200210022×227×50\frac{Z^2 - R^2}{2 \pi \nu} = \frac{200^2 - 100^2}{2 \times \frac{22}{7} \times 50} = 0.55 H