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Question

Chemistry Question on Thermodynamics

When 11 \, mole of CO2(g)CO_{2(g)} occupying volume 10L10\,L at 27C27^{\circ}C is expanded under adiabatic condition, temperature falls to 150K150\, K. Hence, final volume is

A

5L5 \,L

B

20L20 \,L

C

40L40\, L

D

80L80\, L

Answer

80L80\, L

Explanation

Solution

For adiabatic expansion T2T1=(V1V2)γ1\frac{T_{2}}{T_{1}}=\left(\frac{V_{1}}{V_{2}}\right)^{\gamma-1} Here, for CO2CO _{2} (triatomic gas), γ=1.33\gamma=1.33 (150300)=(10V2)0.33\therefore\left(\frac{150}{300}\right)=\left(\frac{10}{V_{2}}\right)^{0.33} or (12)=(10V2)0.33\left(\frac{1}{2}\right)=\left(\frac{10}{V_{2}}\right)^{0.33} or (12)3=10V2\left(\frac{1}{2}\right)^{3}=\frac{10}{V_{2}} or 18=10V2\frac{1}{8}=\frac{10}{V_{2}} or V2=80LV_{2}=80\, L