Question

When 0.5 ampere of electricity is passed in aqueous solution of $AgNO_3$ for 200 seconds,the amount of silver deposited on cathode is(Z = 0 001118 g C'for Ag)

• A. 0 1118 g
• B. 0.0118 g
• C. 0.9560 g
• D. 0.00956 g

Answer 1

Answer: (A)

0 1118 g

Answer 2

$W = Zit = 0.001118 \times 0.5 \times 200$ $= 0.1118\,g$ of $Ag$.