What would happen when a solution of potassium chromate is t... | Chemistry | SolveeIt

Question

What would happen when a solution of potassium chromate is treated with an excess of dilute nitric acid?

$Cr^{3+}$ and $Cr_2O^{2-}_7$ are formed

$Cr_2O_7^{2-}$ and $H_2O$ are formed

$CrO^{2-}_4$ is reduced to $+3$ state of $Cr$

$CrO^{2-}_4$ is oxidised to $+7$ state of $Cr$

Answer

$Cr_2O_7^{2-}$ and $H_2O$ are formed

Explanation

Solution

Dilute nitric acid converts chromate into dichromate and $H_2O$ . ${2K2CrO2 + 2HNO3 -> K2Cr2O7 + 2KNO3 + H2O}$ or, $\underset{\text{yellow}}{\cf{2CrO^{2-}4}}$ ${<=>[H^+] }$ $\underset{\text{orange}}{\cf{Cr2O^{2-}7}}$ $+ H_2 O$

Chemistry Question on d -and f -Block Elements

Solution