Question
Question: What would be the major product of the following reaction?  in liquid that contains stoichiometric amounts of an alcohol such as ethanol.
In the given question, we have line annotation of the organic compound alkyne. So, we convert it to the carbon and hydrogen form. When we react with the given reagent with sodium and liquid ammonia, birch reduction takes place and a trans product is formed. The Trans product has to be converted back to line annotation. Also the same branched reaction can be given as;
H3C−CH2−C2−CH3NaNH3(l)H5C2−CH=CH−CH3
Therefore, the correct option is B.
Additional Information: While cis isomers are generally polar, the same cannot be said for Tran’s forms as they are generally referred to as non - polar molecules. The melting point of cis isomer are relatively lesser than Trans because of the packaging of molecules is tightly in trans form. The boiling point of cis is greater than trans isomers because of strong attractive forces in cis isomer. Cis and Trans are the geometrical isomers. In cis isomers, same groups are present on the same side of double bond while in Trans, the group on one side of isomer is different.
Note:
Remember that while doing the conversion reactions in organic chemistry, we should pay specific attention to the reagents as smaller changes in them can change the products completely. The conversion of alkyne to trans-alkene by Birch reduction using alkali metals (such as Na or K ) in liquid and alcohol (MeOH or EtOH), four radicals are formed i.e. radical anion, vinylic radical, trans-vinylic anion, trans alkene.