Question

What will happen when diethyl ether is treated with hot and concentrate HI?
A.Ethyl alcohol
B.Ethyl iodide
C.Methyl iodide
D.Methanol

Answer 1

Diethyl ether reacts with con. HI. The reaction takes place and gives the product of alcohol and iodide. The reaction occurs between two reactants and finally react with each other and give product.

Complete step by step answer:
Diethyl ether contains ether groups and reacts with hot and concentrated acid of HI.
When the reaction takes place, the product is formed of alcohol and iodide.
This reaction contains $S{N^1}$ reaction.
The reaction is given as below,
$C{H_3} - C{H_{{2_{}}}} - O - C{H_2} - C{H_3} + Conc.HI \to C{H_3} - C{H_2} - OH + C{H_3} - C{H_2} - I$

Here, we take reaction between diethyl ether with conc.HI. So we get the both products of ethyl alcohol and ethyl iodide.

Hence, the correct options are both option (A) and option (B).

Additional information:
The formula of diethyl ether is ${({C_2}{H_5})_2}O$ . It is a colorless, highly volatile, sweet smelling, flammable liquid. It is used as a general anesthetic. Diethyl ether contains structural isomers of butanol. The uses of diethyl ether is in fuel, laboratory, anesthetic, and recreational.

Note:
HI is known as hydriodic acid. It is a very strong acid. It used to prepare iodides by reaction.It is commonly used as reducing agent and production of acetic acid. HI is a colourless gas, it has sharp odour which is dissolved in water.HI is corrosive acid.HI has the ability to lose a proton or take it during chemical reaction.