Question

What will be the work done when one mole of a gas expands isothermally from 15 L to 50 L against a constant pressure of 1 atm at $25^{o}C$?

• A. – 3542 cal
• B. $- 843.3$cal
• C. – 718 cal
• D. $- 60.23$ cal

Answer 1

Answer: (C)

– 718 cal

Answer 2

: Work done in reversible isothermal expansion,

$W = - 2.303nRT\log\frac{V_{2}}{V_{1}}$

$= - 2.303 \times 1 \times 2 \times 298 \times \log\frac{50}{15} = - 717.8cal$

(R = 2 cal $K^{- 1}mol^{- 1}$)