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Question

Chemistry Question on Some basic concepts of chemistry

What will be the weight of COCO having the same number of oxygen atoms as present in 22g22\, g of CO2CO_{2}?

A

28g28\,g

B

22g22\,g

C

44g44\,g

D

72g72\,g

Answer

28g28\,g

Explanation

Solution

No. of OO atoms in CO2=2CO_2 = 2 Molar mass of CO2=44gCO_2 = 44\, g 44g1 44 \,g \equiv 1 mol 22g0.5\Rightarrow 22\, g \equiv 0.5 mol 11 mole of CO2CO_2 contains =2×6.023×1023O= 2 \times 6.023\times 10^{23} O atoms 0.5 0.5 mole of CO2=6.023×1023OCO_2 = 6.023 \times 10^{23} O atoms 1 1 mole of CO=6.023×1023OCO = 6.023 \times 10^{23} O atoms Mass of 11 mole of CO=12+16=28gCO = 12 + 16 = 28\, g