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Question

Question: What will be the wavelength of an electron moving with \(\frac{1}{10}th\) of velocity of light?...

What will be the wavelength of an electron moving with 110th\frac{1}{10}th of velocity of light?

A

2.43×1011m2.43 \times 10^{- 11}m

B

243×1011m243 \times 10^{- 11}m

C

0.243m0.243m

D

2.43×104m2.43 \times 10^{- 4}m

Answer

2.43×1011m2.43 \times 10^{- 11}m

Explanation

Solution

: v=3×10810=3×107ms1v = \frac{3 \times 10^{8}}{10} = 3 \times 10^{7}ms^{- 1}

λ=hmv=6.626×1034Js9.1×1031kg×3×107ms1\lambda = \frac{h}{mv} = \frac{6.626 \times 10^{- 34}Js}{9.1 \times 10^{- 31}kg \times 3 \times 10^{7}ms^{- 1}}

=2.43×1011m= 2.43 \times 10^{- 11}m