Question

What will be the volume of $2.8$g of carbon monoxide at $27^{0}C$ and $0.821$atmospheric pressure is?

• A. $2.5L$
• B. 4L
• C. $3.5L$
• D. 3 L

Answer 1

Answer: (D)

3 L

Answer 2

: $n = \frac{m}{M} = \frac{2.8}{28} = 0.1$

$V = \frac{nRT}{p} = \frac{0.1 \times 0.0821 \times 300}{0.821}$