Question

What will be the strength of 20 vol of $H_{2}O_{2}$in terms of gram per litre?

• A. $60.71gL^{- 1}$
• B. $5.6gL^{- 1}$
• C. $30.62gL^{- 1}$
• D. $17gL^{- 1}$

Answer 1

Answer: (A)

$60.71gL^{- 1}$

Answer 2

: 20 vol of $H_{2}O_{2}$means :

1 L of this $H_{2}O_{2}$will give 20 L of oxygen at STP.

$\underset{2 \times 34}{2H_{2}O_{2}} \rightarrow \underset{22.4LatSTP}{O_{2}} + H_{2}O$

$22.4L$of $O_{2}$is produced from 68 g of $H_{2}O_{2}$

$20L$of $O_{2}$is produced from

$= \frac{68 \times 20}{22.4} = 60.71gL^{- 1}$ of $H_{2}O_{2}$