Question
Question: What will be the reading of the voltmeter which has been shown below? −(1×I)−1−1−1−(1×I)=0
Let us simplify this equation in order to obtain the value of current. That is,
3I=3∴I=1A
As we can see the voltage will be the same in both the branches as they are parallel in nature. In order to find the voltage shown in the voltmeter, therefore we can consider only one branch. Therefore now the lower branch in the circuit can be shown as,
Let us apply Kirchhoff's voltage law in this equation. That is we can write that,
0+6−1×1−1×1=4V
Hence the reading of the voltmeter will be equivalent to 4V. This has been mentioned as option C.
Note:
Kirchhoff’s Current Law can be otherwise called by several names as Kirchhoff’s First Law and Kirchhoff’s Junction Rule. This junction rule says that, in a circuit, the sum of the currents in a junction will be equal to the sum of currents outside the junction. Kirchhoff’s Voltage Law can be otherwise known as Kirchhoff’s Second Law and Kirchhoff’s Loop Rule.