Question
Question: What will be the product of the following reaction?  shifts to the carbocation so ring contraction takes place forming a five-membered ring. The carbocation forms at another carbon and hydroxyl group attached with that carbon donating its lone pair to the carbocation. Final removal of a proton from the hydroxyl group forms ketone.
As the reactant has two hydroxyl groups. The hydroxyl group present at the axial position can also attack the proton and get protonated. By the removal of a water molecule, a carbocation will forms. The methyl group at the adjacent carbon is Trans to the carbocation so, methyl group will transfer to the carbocation and the carbocation forms at another carbon and hydroxyl group attached with that carbon donate its lone pair to the carbocation. Final removal of a proton from the hydroxyl group forms ketone.
The mechanism of the rearrangement is shown as follows:
Therefore, the correct answer is (C).
Note: The pinacol-pinacolone rearrangement takes place in acidic medium. The 1,2 axial-axial position of diol is known as Trans. The Trans 1,2diol does not give pinacol-pinacolone rearrangement because in Trans 1,2diol, no migratory group is present. The 1,2 axial-equatorial position of diol is known as cis. Cis give the pinacole-pinacolone rearrangement. In the absence of a migratory group at Trans position, the ring contraction takes place. The migratory aptitude is H > aryl > alkyl.