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Question: What will be the pressure of the gas mixture of \(3.2g\)methane and \(4.4g\)carbon dioxide contained...

What will be the pressure of the gas mixture of 3.2g3.2gmethane and 4.4g4.4gcarbon dioxide contained in a 9 dm3dm^{3}flask at 270C27^{0}C?

A

0.82atm0.82atm

B

8.314×104atm8.314 \times 10^{4}atm

C

1 atm

D

1.8atm1.8atm

Answer

0.82atm0.82atm

Explanation

Solution

: P=nvRTP = \frac{n}{v}RT

n for CH4=3.216=0.2;nforCO2=4.444=0.1CH_{4} = \frac{3.2}{16} = 0.2;nforCO_{2} = \frac{4.4}{44} = 0.1

ntotal=0.2+0.1=0.3n_{total} = 0.2 + 0.1 = 0.3

P=0.3×0.0821×3009=0.82atmP = \frac{0.3 \times 0.0821 \times 300}{9} = 0.82atm