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Question

Chemistry Question on Equilibrium

What will be the pHpH of 0.1M0.1\, M ammonium acetate solution? (pKa=pKb=4.74)\left(p K_{a}=p K_{b}=4.74\right)

A

4.74

B

6.74

C

7.74

D

7

Answer

7

Explanation

Solution

Ammonium acetate (CH3COONH4)\left( CH _{3} COONH _{4}\right) is a salt of weak acid and weak base.
pH=7+12(pKapKb)p H=7+\frac{1}{2}\left(p K_{a}-p K_{b}\right)
Given that, pKa=pKb=4.74p K_{a}=p K_{b}=4.74
Putting that values, we get
pH=7+12(4.744.74)=7+0=7p H=7+\frac{1}{2}(4.74-4.74)=7+0=7