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Question: What will be the osmotic pressure in Pascals exerted by a solution prepared by dissolving \(1.0\)g o...

What will be the osmotic pressure in Pascals exerted by a solution prepared by dissolving 1.01.0g of polymer molar mass 150, 000 in 500 mL of water at 37º?37º?

A

30.96Pa30.96Pa

B

34.36Pa34.36Pa

C

68.72Pa68.72Pa

D

48.25Pa48.25Pa

Answer

34.36Pa34.36Pa

Explanation

Solution

No. of moles of polymer =1150,000= \frac{1}{150,000}

π=crT=nVRT\pi = crT = \frac{n}{V}RT

π=1150,000×8.314×103×3100.5=34.36Pa\pi = \frac{1}{150,000} \times \frac{8.314 \times 10^{3} \times 310}{0.5} = 34.36Pa

(R=8.314×103PaLK1mol1R = 8.314 \times 10^{3}PaLK^{- 1}mol^{- 1})