Question

What will be the most suitable combination of three resistors A = 2 Ω, B = 4 Ω, C = 6 Ω so that $(22/3)$ Ω is equivalent resistance of combination?

• A. Parallel combination of A and C connected in series with B.
• B. Parallel combination of A and B connected in series with C
• C. Series combination of A and C connected in parallel with B.
• D. Series combination of B and C connected in parallel with A.

Answer 1

Answer: (B)

Parallel combination of A and B connected in series with C

Answer 2

$R_{eq} = \frac{2\times 4}{2+6}+6=\frac{22}{3}$
⇒ A and B are in parallel and C is in series.