Question

What will be the melting point of KCl if enthalpy change for the reaction is $7.25Jmol^{- 1}$ and entropy change is $0.007JK^{- 1}mol^{- 1}$?

• A. $1835.2K$
• B. 173 K
• C. $1035.7K$
• D. $1285.2K$

Answer 1

Answer: (C)

$1035.7K$

Answer 2

: $T = \frac{\Delta H}{\Delta S} = \frac{7.25}{0.007} = 1035.7K$