Question

What will be the melting point of $KCl$ if enthalpy change for the reaction is $7.25\, J\, mol^{-1}$ and entropy change is $0.007\, J \,K^{-1}\, mol^{-1}$ ?

• A. $1835.2 \,K$
• B. $173 \,K$
• C. $1035.7 \,K$
• D. $1285.2 \,K$

Answer 1

Answer: (C)

$1035.7 \,K$

Answer 2

$T = \frac{\Delta H}{\Delta S} = \frac{7.25}{0.007}$ $= 1035.7\,K$