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Question: What will be the mass of a particle if uncertainty in its position is \(10^{- 8}\) m and velocity is...

What will be the mass of a particle if uncertainty in its position is 10−810^{- 8} m and velocity is 5.26×10−25ms−15.26 \times 10^{- 25}ms^{- 1}?

A

0.010.01 kg

B

0.10.1kg

C

1 kg

D

10 kg

Answer

0.010.01 kg

Explanation

Solution

: Δx.mΔv=h4π\Delta x.m\Delta v = \frac{h}{4\pi}

10−8m×m×5.26×10−25ms−1=6.626×10−34Js4×3.1410^{- 8}m \times m \times 5.26 \times 10^{- 25}ms^{- 1} = \frac{6.626 \times 10^{- 34}Js}{4 \times 3.14}

m=6.626×10−34Js4×3.14×10−8m×5.26×10−25ms−1=0.01kgm = \frac{6.626 \times 10^{- 34}Js}{4 \times 3.14 \times 10^{- 8}m \times 5.26 \times 10^{- 25}ms^{- 1}} = 0.01kg