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Question

Question: What will be the mass of \(2\) moles of \[MgS{O_4}\]?...

What will be the mass of 22 moles of MgSO4MgS{O_4}?

Explanation

Solution

We need to know that the MgSO4MgS{O_4} is an inorganic compound known as magnesium sulphate. It contains three types of elements: magnesium, sulfur and oxygen. A mole is defined as 6.02214076×10236.02214076 \times {10^{23}} of some chemical unit, be it atoms, molecules, ions, or others.

Complete answer:
To solve this question we must know before what exactly the atomic mass of the particular element, atom or ion or compound given. Firstly we need to calculate the atomic mass of MgSO4MgS{O_4} .The atomic mass of magnesium is 2424, atomic mass of sulfur is 3232 and atomic mass of oxygen is 1616 since there are four oxygen atoms so the total mass of oxygen will be 6464. In total the atomic mass of magnesium sulphate comes out by adding the individual masses of all the atoms so the atomic mass of magnesium sulphate is 24+32+6424 + 32 + 64, so the mass comes out to be 120g/mol120g/mol. One mole of magnesium sulphate contains 120g120g , so two moles of magnesium sulphate will be 240g240g. Number of moles can be calculated by using the formula given weight of any element or compound divided by the molecular weight of the same element or compound given.

Note:
We need to know that the mass of a mole of substance is called the molar mass of that substance. The molar mass is used to convert grams of a substance to moles and is used often in chemistry. The molar mass of an element is found on the periodic table, and it is the element's atomic weight in g/molg/mol .If the mass of a substance is known, the number of moles in the substance can be calculated.