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Question: What will be the kinetic energy of oxygen gas at \(27^{0}C\)?...

What will be the kinetic energy of oxygen gas at 270C27^{0}C?

A

37.413×102JK−1mol−137.413 \times 10^{2}JK^{- 1}mol^{- 1}

B

27.5×109JK−1mol−127.5 \times 10^{9}JK^{- 1}mol^{- 1}

C

1.934×105JK−1mol−11.934 \times 10^{5}JK^{- 1}mol^{- 1}

D

8.314JK−1mol−18.314JK^{- 1}mol^{- 1}

Answer

37.413×102JK−1mol−137.413 \times 10^{2}JK^{- 1}mol^{- 1}

Explanation

Solution

: K.E. =32RT=32×8.314×300\frac{3}{2}RT = \frac{3}{2} \times 8.314 \times 300

=37.413×102Jk−1mol−137.413 \times 10^{2}Jk^{- 1}mol^{- 1}