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Question: What will be the fraction which will remain after a time \(\dfrac{T}{2}\), if the half life of radio...

What will be the fraction which will remain after a time T2\dfrac{T}{2}, if the half life of radioactive is TT?
A) 12\dfrac{1}{{\sqrt 2 }}
B) 212\dfrac{{\sqrt 2 - 1}}{{\sqrt 2 }}
C) 12\dfrac{1}{2}
D) 34\dfrac{3}{4}

Explanation

Solution

Hint: - The half – life is the time which is required to reduce the half of the value of the given quantity. It is also used to describe how quickly unstable atoms undergo or how long the stable atoms will survive the decaying of radioactive.

Complete step by step answer:
The half – life can be defined as the time required to reduce the half of the initial value of the given quantity. It is also used to describe how quickly unstable atoms undergo or how long the stable atoms will survive the decaying of radioactive. It can also determine type of exponential and non – exponential decay.
The formula for half – life in exponential decay is –
NN0=(12)tt12(1) NN0=etT(2) NN0=eλt(3)  \mapsto \dfrac{N}{{{N_0}}} = {\left( {\dfrac{1}{2}} \right)^{\dfrac{t}{{{t_{\dfrac{1}{2}}}}}}} \cdots \left( 1 \right) \\\ \mapsto \dfrac{N}{{{N_0}}} = {e^{\dfrac{{ - t}}{T}}} \cdots \left( 2 \right) \\\ \mapsto \dfrac{N}{{{N_0}}} = {e^{ - \lambda t}} \cdots \left( 3 \right) \\\
where, N0{N_0} is the initial value of the substance which will decay
NN is the quantity which has not decayed even after time tt and is still remaining
t12{t_{\dfrac{1}{2}}} is the half – life of the quantity which will decay
TT is the average lifetime of the quantity which will decay
λ\lambda is the decay constant
The exponential decay can be determined by using any of the above equivalent formulas.
So, for solving the question we will use the equation (1)\left( 1 \right) -
NN0=(12)n NN0=(12)tT  \dfrac{N}{{{N_0}}} = {\left( {\dfrac{1}{2}} \right)^n} \\\ \dfrac{N}{{{N_0}}} = {\left( {\dfrac{1}{2}} \right)^{\dfrac{t}{T}}} \\\
We know that from question, t=T2t = \dfrac{T}{2}
NN0=(12)T2T NN0=(12)12 NN0=12  \therefore \dfrac{N}{{{N_0}}} = {\left( {\dfrac{1}{2}} \right)^{\dfrac{{\dfrac{T}{2}}}{T}}} \\\ \dfrac{N}{{{N_0}}} = {\left( {\dfrac{1}{2}} \right)^{\dfrac{1}{2}}} \\\ \dfrac{N}{{{N_0}}} = \dfrac{1}{{\sqrt 2 }} \\\
Hence, the fraction remaining after time T2\dfrac{T}{2} is 12\dfrac{1}{{\sqrt 2 }}.

Therefore, the correct option is (A).

Note: - Half – life becomes constant over the lifetime of an exponentially decaying quantity. Usually, it can also describe the discrete entities decay. The entity's decay can be radioactive atoms. Then, the half – life can also be defined as time required for the decay of half of the entities.