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Question

Physics Question on Current electricity

What will be the equivalent resistance between the two points A and D?

A

30Ω30\, \Omega

B

40Ω40\, \Omega

C

10Ω10\, \Omega

D

50Ω50\, \Omega

Answer

30Ω30\, \Omega

Explanation

Solution

Lower resistance on extreme left and upper resistance on extreme right are ineffective.
The resistance R2R_2 and R3R_3 are in series combination.
Therefore their equivalent resistance, R=R2+R3=10+10=20Ω.R' = R_2+R_3 = 10+10 = 20\, \Omega. Similarly, the resistance R5R_5 and R6R_6 are in series combination.
Therefore their equivalent resistance, R" =R5+R6=10+10=20Ω. = R_5+R_6 = 10+10 = 20\, \Omega. Now the equivalent resistances R' and R'' are in parallel combination.
Therefore their equivalent resistance. R=RRR+R=20×2020+20=40040=10Ω. \, \, \, \, R''' =\frac{R' R''}{R'+R''}=\frac{20 \times 20}{20+20}=\frac{400}{40}=10\, \Omega.
Thus equivalent resistance between A and D, R =R1+R+R4=10+10+10=30Ω= R_1+R'''+R_4=10+10+10=30\, \Omega (\because series combination)