Question
Chemistry Question on Equilibrium
What will be the equilibrium constant of the given reaction carried out in a 5L vessel and having equilibrium amounts of A2 and A as 0.5 mole and 2×10−6 mole respectively?
The reaction : A2⇌2A
A
0.16×10−11
B
0.25×105
C
0.4×10−5
D
0.2×10−11
Answer
0.16×10−11
Explanation
Solution
The correct option is(A) : 0.16×10−11
A2⇌2A
Concentration of A2 at equilibrium =50.5
Concentration of A at equilibrium =52×10−6
Equilibrium constant, Kc=[A2][A]2=50.5(52×10−6)2
=25×0.54×5×10−12
=0.16×10−11