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Question: What will be the equation of circle whose centre is (3, –1) and which intercept chord of 6 unit leng...

What will be the equation of circle whose centre is (3, –1) and which intercept chord of 6 unit length on straight line

2x – 5y + 18 = 0

A

x2 +y2 – 6x + 2y – 28 = 0

B

x2 + y2 + 6x – 2y + 28 = 0

C

x2 + y2 + 4x – 2y + 24 = 0

D

x2 + y2 + 2x – 2y – 12 = 0

Answer

x2 +y2 – 6x + 2y – 28 = 0

Explanation

Solution

AB = 6, p = 29\sqrt{29}

Ž 2AD = 6

Ž AD = 3

Ž r2p2\sqrt{r^{2} - p^{2}}= 3

Ž r2 – p2 = 9

Ž r2 – 29 = 9

Ž r2 = 38

Ž r = 38\sqrt{38}

Equation of circle

(x – 3)2 + (y + 1)2 = 38