Question

what will be the energy loss per hour in the iron core of a transform if the area of its hysteresis loop is equivalent to $2500erg/cm^3$ . The frequency of alternating current is 50 Hz. The mass of core is 10 Kg and the density, of iron is $7.5gm/cm^3$

• A. $2 \times 10^2$ joule
• B. $4 \times 10^3$ joule
• C. $6 \times 10^4$ joule
• D. $8 \times 10^5$ joule

Answer 1

Answer: (C)

$6 \times 10^4$ joule

Answer 2

Total energy loss $E = nA Vt = nA \frac{m}{d} t$ $50 \times 2500 \times 10^{-1} \times \frac{10}{7.35 \times 10^3} \times 3600$ = $6 \times 10^4 \, Joule$